2x^2-10x=119

Solution for 2x^2-10x=119 equation:

2x^2-10x=119

We move all terms to the left:

2x^2-10x-(119)=0

a = 2; b = -10; c = -119;
Δ = b2-4ac
Δ = -102-4·2·(-119)
Δ = 1052
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1052}=\sqrt{4*263}=\sqrt{4}*\sqrt{263}=2\sqrt{263}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{263}}{2*2}=\frac{10-2\sqrt{263}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{263}}{2*2}=\frac{10+2\sqrt{263}}{4}
$